Lakhan ate 72 bananas in six days, each day eating 4 more than the previous day. How many bananas did he eat on the second day?
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Answer:
Step-by-step explanation:
here we form an a.p.
let lakhan ate x bananas at first day
then according to question
x , x+4 , (x+4)+4 ...........
here first term a= x
d(common difference)=4
a6 = 72
n= 6
an= a+(n-1)d
72=x+(7-1)4
72=x+ 6×4
72-24=x
48=x
so on second day he eat
x+4=48+4 =52 bananas
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