Question

Lambda square minus 3 times lambda equals to ten gives what value of lambda

Answer 1

Answer:5 or -2

Step-by-step explanation:

Let lambda be x

Then, according to the question,

x^2-3x=10

x^2-3x-10=3

By splitting the middle term we get

x^2-5x+2x-10=0

x(x-5)+2(x-5)=0

(x-5)(x+2)=0

x=5 or x=-2

Lambda is 5 or -2

Answer 2

Answer:

The values of lambda are 2 and 5.

Step-by-step explanation:

Let lambda = x

Then equation will be-

$x^{2} - 3x = 10$

$x^{2} - 3x -10 =0$

$x^{2} -(5-2)x -10 = 0$

$x^{2} - 5x - 2x - 10 = 0$

x(x - 5) -2(x - 5) = 0

(x - 5)(x - 2) = 0

If x - 5 = 0 then

x = 5

If x - 2 = 0 then

x = 2

So, lambda = 2, 5

Hence, the values of lambda are 2 and 5.