Lana collects 20-cent coins and 50 cent coins. The total value of her coins is currently $9.70. If Lana has 4 more 50-cent coins than 20-cent coins how many of each type does she have?
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Answer:
20x + 50y = 970
y=4+x
x=y-4
20(y-4) + 50y = 970
-80 + 20 y + 50y = 970
70y = 1050
y = 1050/70 = 15
x=11
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Given : Lana collects 20-cent coins and 50 cent coins. The total value of her coins is currently $9.70. If Lana has 4 more 50-cent coins than 20-cent coins
To Find : how many of each type does she have?
Solution:
20 cents coins = x
50-cent coins = x + 4
20 cents coins value = 20x cents
50 cents coins value = 50(x + 4) = 50x + 200 cents
Total Value = 20x + 50x + 200
= 70x + 200 cents
$9.70 = 970 cents
70x + 200 cents = 970
=> 70x = 770
=> 7x = 77
=> x = 11
20 cents coins = 11
50-cent coins = 15
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