Lana is studying a chemical reaction in which the reactants propane (C3H8) and oxygen gas (O2) react to yield the products carbon dioxide (CO2) and water (H2O). Lana's teacher informs her that two molecules of propane and ten molecules of oxygen are reacting. The teacher then asks Lana to assess how many molecules of carbon dioxide and water will be produced in the reaction.
What should Lana do to determine the answer to her teacher's question?
A) Lana should list each element's state of matter, because the law of conservation of mass declares that the states of matter present on the reactant side must be equal to or greater than the states of matter present on the product side.
B) Lana should list each element's state of matter, because the law of conservation of energy declares that the states of matter present on the reactant side will transform into their corresponding states of matter on the product side.
C) Lana should write and balance the chemical equation, because the law of conservation of mass states that the number of atoms for each element in the reactants must equal the number of atoms for each element in the products.
D) It is not possible for Lana to determine the answer to her teacher's question.
E) Lana should write and balance the chemical equation, because the law of conservation of energy states that the number of atoms in each element influences the amount of energy that can be used to produce a limited number of products.
Answers
Answer:
Your answer will be option c.
Hope this helps u.
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In such type of problems where reactant and product ratios are calculated one (Launa) should take start from balanced chemical equation. A balanced chemical equations helps in solving such problems. For this purpose chemical equation of this combustion reaction is drawn.
Equation:
C₃H₁₀ ⁺ 5 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 3 CO₂ ⁺ 4 H₂O
Now, According to this balanced equation one molecule of propane reacts with 5 molecules of oxygen to produce 3 molecules of carbon dioxide and 4 molecules of water.
As She is given with 2 molecules of propane and 10 molecules of oxygen, which means that the equation is multiplied by 2. So, the product side must also be multiplied by 2 to balance the equatio (Law of Conservation of Mass).
Result:
( C₃H₁₀ ⁺ 5 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 3 CO₂ ⁺ 4 H₂O ) ₓ 2
2 C₃H₁₀ ⁺ 10 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 6 CO₂ ⁺ 8 H₂O
So, 6 molecules of carbon dioxide and 8 molecules of water are produced.