laplace(1-e^-t).....Find laplace transform of the same
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Mate I can't able to getting your question. plz clear it....xd
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0
Answer:
δ(s) - δ(s - 1)
Step-by-step explanation:
as the laplace of 1 is 1/s
and the laplace of e^-t is 1/(s+1)
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