Question

Laplace inverse of 1/s+1^2​

Answer 1

Answer:

this is an example not answer "khud solve karo"

Step-by-step explanation:

Let us solve this by taking Laplace formula first

L(t n ) = Gamma(n+1)/s^(n+1)

// since n is fractional (non-integral) value here

now here for n+1 to be .5 ,

n comes out to be -.5 = -1/2

Therefore L^(-1) is t^(-1/2)/(gamma(1/2))

that is t^(-1/2)/pi^(1/2).