Question

Laplace of [e^-2t sin3t dt]​

Answer 1

Answer:

bhai kya que. pucha hai maja aa gaya

Step-by-step explanation:

the table.

L(e−tsin2t)=2(s+1)2+4◂=▸L⁡(◂⋅▸e−t⁢sin⁡2⁢t)=2◂◽˙▸(s+1)2+4, using frequency shifting.

L(te−tsin2t)=−dds(2(s+1)2+4)