Math, asked by vidya882001, 3 months ago

Laplace transform of t sint is​

Answers

Answered by abdulraziq1534
0

Concept Introduction:-

The integral transformation of a real-valued derivative into a more sophisticated function is known Laplase transform.

Given Information:-

We have been given that  t sint

To Find:-

We have to find that the value of t sint

Solution:-

According to the problem

The Laplace transform of

=(-1)^{1} \frac{d}{d s}(L\{\sin (t)\})\\L\{\sin (t)\}: \frac{1}{s^{2}+1}\\\frac{d}{d s}\left(\frac{1}{s^{2}+1}\right)=-\frac{2 s}{\left(s^{2}+1\right)^{2}}\\=(-1)^{1}\left(-\frac{2 s}{\left(s^{2}+1\right)^{2}}\right)\\=\frac{2 s}{\left(s^{2}+1\right)^{2}}.

Final Answer:-

Laplace transform of t sint is​ \frac{2 s}{\left(s^{2}+1\right)^{2}}.

#SPJ3

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