Question

large storage tank contains a salt solution of variable density given by ρ = 1050 +kh in kg/m3

, at a

depth h metres below the free surface. Calculate the pressure intensity at the bottom of the tank

holding 5 m of the solution.​

Answer 1

Explanation:

Pressure (P) at the bottom of the tank is given by P=hdg

=1m×1000kg×9.8ms

−2

=9800Nm

−2

Surface area at the bottom of the tank =2m×1.5m=3m

2

∴Thrustatthebottomofthetank=force×area

=9800Nm

−2

×3m

2

=29,400N.

Answer 2

Pressure (P) at the bottom of the tank is given by

P=hdg

=1m×1000kg×9.8$ms^{-2}$

=9800$Nm^{-2}$

Surface area at the bottom of the tank =2m×1.5m=3$m^{2}$

Thus the bottom of the tank=force×area=9800$Nm^{-2}$×3$m^{2}$

                                                                        =29,400N.