Question

largest 4 digit number when divided by 4, 17, 13 leaves remainder 3 pls need ans now....

Answer 1

Step-by-step explanation:

LCM( 4,7,13)=4*7*13=364

Now largest 4 digit number=9999

9999=27*364+171

=9828+171

Thus largest 4 digit number divisible by 4,7,13 is 9828

In each case the remainder is 3

Thus the required number=9828+3=9831

Answer 2

$\star\;{\underline{\underline{\sf{\pink{QueStion\;\;:}}}}}$

largest 4 digit number when divided by 4, 17, 13 leaves remainder 3.

$\huge\star{\underline{\mathtt{\red{A}\pink{N}</p><p>\green{S}\blue{W}\purple{E}\orange{R}}}}\star$

${\red{\boxed{\large{\bold{largest\: 4\: digit \: num. = 9999}}}}}$

9999÷4=leaves remainder 3(refer to the attachment)

9999÷17=leaves remainder 3(refer to the attachment)

9999÷13=leaves remainder 2(refer to the attachment)

therefore,

9999 when divided with 4,17 leaves remainder 3 and when divided with 13 leaves remainder 2