largest 5digit exactly divisible by 40
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Answered by
344
largest 5digit no. is 99999.
so, largest no. divisible by 40 is = 99999/40
=2499.97
so, the largest 5digit no. divisible by 40 is 40×2499 = 99960
so, largest no. divisible by 40 is = 99999/40
=2499.97
so, the largest 5digit no. divisible by 40 is 40×2499 = 99960
Answered by
87
Answer:
The largest 5 digit number exactly divisible by 40 is 99960.
Step-by-step explanation:
A number is divisible by 40, if the number ends with 0; i.e. the last digit must be 0.
So in a five digit number, the last number that is the 5th number should be 0
Out of the 4 remaining digits, the last 2 digits must be divisible by 4. [Divisibility rule of 4.]
According the largest 2digit number that can be divided by 4 is 96.
Thus, the last 3 digits of the 5 digit number is 960.
And, the largest 5-digit number which exactly divisible by 40 is 99960.
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