Question

largest no which exactly divides 280 and 1245 leaving remainders 4 and 3

Answer 1

Given 280 leaving remainder 4 = 280 - 4 = 276.

Given 1245 leaving remainder 3 = 1245 - 3 = 1242.

HCF of 276 = 2 * 2 * 3 * 23

HCF of 1242 = 2 * 3 * 3 * 3 * 23

HCF of 276 and 1242 = 2 * 3 * 23

                                    = 138.

Largest number will be 138.


Hope this helps!

Answer 2

Answer:

Given 280 leaving remainder 4 = 280 - 4 = 276.

Given 1245 leaving remainder 3 = 1245 - 3 = 1242.

HCF of 276 = 2 * 2 * 3 * 23

HCF of 1242 = 2 * 3 * 3 * 3 * 23

HCF of 276 and 1242 = 2 * 3 * 23

                                   = 138.

Largest number will be 138.