Largest wavelength in Balmer series of hydrogen atom is 6563 Å. Minimum wavelength of this series is
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Since wavelength and energy are inversely related, the longest wavelength would be produced by the lowest amount of energy. That would be by the electron falling from from n = 3 (ni) to n = 2 (nf). (All Balmer series lines have nf = 2). lambda = 1 / (1.52 x 10^6 m) = 6.56 x 10^-7 m = 656 nm . . .that's a RED line.
364 nm
This is also known as the Hα line of atomic hydrogen and is bight red (Figure 1.4. 4). Since 1˜ν=λ in units of cm, this converts to 364 nm as the shortest wavelength possible for the Balmer series.
Explanation:
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