Math, asked by nnasir1026, 8 months ago

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Larry had some money in his wallet. When he goes to the store he sees that bag of chips is $2, soft pretzels are $1.25, and a can of pop is $0.50. With the money he has, Larry can buy 4 bags of chips, 3 soft pretzels, and 2 cans of pop. How much money did Larry have?

Answers

Answered by JuveriyaF
2

Answer: $12.75

Solution:

cost of a bag of chips= $2

No. of bags that Larry can afford=4

Money spent on bags of chips= 2×4

= $8

Cost of soft pretzels=$1.25

Amount that Larry can afford=3

Money spent= 3×1.25

=$3.75

Cost of a can of pop= $0.50

No. of cans he can purchase= 2

Money spent= 2×0.50

=$1.0=$1

Therefore, total amount of money that Larry had in his wallet= $8 + $ 3.75 + $1

= $12.75

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