Question

Laser action occurrs by stimulated emission from an excited state to a state of energy 30.5eV. If the wavelength of LASER light emitted in 690 nm. What is the energy of the excited one.

Answer 1

Answer:

30 open of bottle

Explanation:

because engrry of the wavelength

Answer 2

Answer:

E2=28.71eV

Explanation:

concept - ∆E= 12400/λeV

given- E1= 30.5eV

λ= 690nm

find- energy in excited state that is ,E2

explanation- ∆E= 12400/λeV

690nm=6900A°

∆E = 12400/6900

∆E= 1.79eV

∆E=E1-E2

∆E= 30.5-E2

1.79=30.5-E2

E2= 30.5-1.79

E2=28.71eV

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