Math, asked by remantkakkar5451, 11 months ago

Last 3 digits of the number n=7^100-3^100

Answers

Answered by Anonymous

1

Answer:

(7-3)^100

Step-by-step explanation:

7^100-3^100

we use this formula

a^n-b^n=(a-b)^n

so 7^100-3^100=(7-3)^100

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