Question

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7. A godown measures 40m x 25 m x 15 m. Find the maximum number of wooden crates
each measuring 1.5 m x 1.25 mx0.5m that can be stored in the godown.
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Answer 1

Correct Question -

A godown measures 40m x 25 m x 15 m. Find the maximum number of wooden crates each measuring 1.5 m x 1.25 m x 0.5m that can be stored in the godown.

Answer -

16000 wooden crates

Given -

• Dimensions of godown = 40m × 25m × 15m

• Dimensions of crates = 1.5m × 1.25m × 0.5m

To find -

• Number of crates that can be stored.

Solution -

Area of cuboid = Length × Breadth × Height

A godown measure = 40m × 25m × 15 m .

So,

Area = 40m × 25m × 15m

Area = 15000 m³

Similarly,

Area of crates = Length × Breadth × height

Area of crates = 1.5 × 1.25 × 0.5

Area of crates = 0.9375 m³

Now,

Let us assume that the number of wooden crates stored in the godown be x .

Equation will be like -

$\longmapsto$ 5000 = x × 0.9375

$\longmapsto$ 15000 = 0.9375x

$\longmapsto$ $\sf x = \cancel{\dfrac{15000}{0.9375}}$

$\longmapsto$ x = 16000

$\therefore$ the number of wooden crates stored in the godown are 16000.

______________________________________

Answer 2

Answer:

Given :-

• Measure of gowdown = 40 × 25 × 15
• Measure of wooden crates = 1.5 × 1.25 × 0.5

To Find :-

Wooden crates required

Solution :-

So, for finding we will first find volume of gowdown and wooden crates

$\rule{200}{8}$

Volume of Gowdown

Volume = Length × Breadth × Height

Volume = 40 × 25 × 15

Volume = 15000 m³

Now,

Let's find volume of wooden crate

$\rule{200}{8}$

We can write

Volume = Length×Breadth×Height

Volume = 1.5×1.25×0.25

Volume = 0.9375 m

Now,

Let's find total wood crates required

$\bf Total crate = \dfrac{Volume of Gowdown}{Volume of one crate}$

Total crate = 15000/0.9375

Total crate required = 16,000.