Last question GN
504 cones, each of diameter 3.5 cm and height 3 cm are melted and recast into a metallic sphere.find the diameter of the sphere and hence find its surface area. [ use π = 22/7]
phirends are allowed including Domb
Answers
Step-by-step explanation:
● We can find the answer using volume and area formula of required shapes.
● The formula for the surface area of a right circular cone is SA = r² + rl.
● The formula for the volume of a right circular cone is V = (r²h)/3.
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Solution
According to the question,
Now, Volume of sphere = Volume of metal in 504 cones
Additional Information :
- Volume of cylinder = πr²h
- T.S.A of cylinder = 2πrh + 2πr²
- Volume of cone = ⅓ πr²h
- C.S.A of cone = πrl
- T.S.A of cone = πrl + πr²
- Volume of cuboid = l × b × h
- C.S.A of cuboid = 2(l + b)h
- T.S.A of cuboid = 2(lb + bh + lh)
- C.S.A of cube = 4a²
- T.S.A of cube = 6a²
- Volume of cube = a³
- Volume of sphere = 4/3πr³
- Surface area of sphere = 4πr²
- Volume of hemisphere = ⅔ πr³
- C.S.A of hemisphere = 2πr²
- T.S.A of hemisphere = 3πr²
Hope it will help you siso ^_^
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