Last question I can’t
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Anonymous:
sorry for providing less information beacuse by mistake i pushed the ans button
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Answered by
1
I think this will be helpful to you
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Answered by
1
ANSWER.
(1)
![101 \times 99 = (100 + 1)99 101 \times 99 = (100 + 1)99](https://tex.z-dn.net/?f=101+%5Ctimes+99+%3D+%28100+%2B+1%2999)
![9900 + 99 9900 + 99](https://tex.z-dn.net/?f=9900+%2B+99)
![9999 9999](https://tex.z-dn.net/?f=9999)
(2)
![53 \times 47 53 \times 47](https://tex.z-dn.net/?f=53+%5Ctimes+47)
![= (50 + 3)(50 - 3) = (50 + 3)(50 - 3)](https://tex.z-dn.net/?f=+%3D+%2850+%2B+3%29%2850+-+3%29)
![{50}^{2} - {3}^{2} {50}^{2} - {3}^{2}](https://tex.z-dn.net/?f=+%7B50%7D%5E%7B2%7D+-+%7B3%7D%5E%7B2%7D+)
![2500 - 9 2500 - 9](https://tex.z-dn.net/?f=2500+-+9)
![2491 2491](https://tex.z-dn.net/?f=2491)
(3)
![{121}^{2} - {119}^{2} {121}^{2} - {119}^{2}](https://tex.z-dn.net/?f=+%7B121%7D%5E%7B2%7D+-+%7B119%7D%5E%7B2%7D+)
![{(120 + 1)}^{2} - {(120 - 1)}^{2} {(120 + 1)}^{2} - {(120 - 1)}^{2}](https://tex.z-dn.net/?f=+%7B%28120+%2B+1%29%7D%5E%7B2%7D+-+%7B%28120+-+1%29%7D%5E%7B2%7D+)
Using formula
![{a}^{2} - {b}^{2} = (a - b)(a + b) {a}^{2} - {b}^{2} = (a - b)(a + b)](https://tex.z-dn.net/?f=+%7Ba%7D%5E%7B2%7D+-+%7Bb%7D%5E%7B2%7D+%3D+%28a+-+b%29%28a+%2B+b%29)
![(120 + 1 + 120 - 1)(120 + 1 - 120 +1) (120 + 1 + 120 - 1)(120 + 1 - 120 +1)](https://tex.z-dn.net/?f=%28120+%2B+1+%2B+120+-+1%29%28120+%2B+1+-+120+%2B1%29)
![240 \times 2 240 \times 2](https://tex.z-dn.net/?f=240+%5Ctimes+2)
![480 480](https://tex.z-dn.net/?f=480)
(4)
![\frac{(23.71 \times 23.71) - (16.29 \times 16.29)}{0.742} \frac{(23.71 \times 23.71) - (16.29 \times 16.29)}{0.742}](https://tex.z-dn.net/?f=+%5Cfrac%7B%2823.71+%5Ctimes+23.71%29+-+%2816.29+%5Ctimes+16.29%29%7D%7B0.742%7D+)
using identity
![{a}^{2} - {b}^{2} = (a - b)(a + b) {a}^{2} - {b}^{2} = (a - b)(a + b)](https://tex.z-dn.net/?f=+%7Ba%7D%5E%7B2%7D+-+%7Bb%7D%5E%7B2%7D+%3D+%28a+-+b%29%28a+%2B+b%29)
![\frac{ {(40.00)}- {(7.42)}}{0.742} \frac{ {(40.00)}- {(7.42)}}{0.742}](https://tex.z-dn.net/?f=+%5Cfrac%7B+%7B%2840.00%29%7D-+%7B%287.42%29%7D%7D%7B0.742%7D+)
=400 ans
(1)
(2)
(3)
Using formula
(4)
using identity
=400 ans
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