Math, asked by hasan51, 11 months ago

Last question I can’t

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Anonymous: sorry for providing less information beacuse by mistake i pushed the ans button
Anonymous: due to which i didn't use latex

Answers

Answered by soundrarajanksr27
1
I think this will be helpful to you
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Answered by Anonymous
1
ANSWER.

(1)

101 \times 99 = (100 + 1)99

9900 + 99

9999

(2)

53 \times 47

 = (50 + 3)(50 - 3)

 {50}^{2} - {3}^{2}

2500 - 9

2491

(3)

 {121}^{2} - {119}^{2}

 {(120 + 1)}^{2} - {(120 - 1)}^{2}

Using formula

 {a}^{2} - {b}^{2} = (a - b)(a + b)

(120 + 1 + 120 - 1)(120 + 1 - 120 +1)

240 \times 2

480

(4)

 \frac{(23.71 \times 23.71) - (16.29 \times 16.29)}{0.742}

using identity

 {a}^{2} - {b}^{2} = (a - b)(a + b)

 \frac{ {(40.00)}- {(7.42)}}{0.742}

=400 ans
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