Question

last question

#linesandangles

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Answer 1

Answer:

hey here is your solution

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Step-by-step explanation:

so here Angle MOY=Angle POY+Angle MOP

=90+a (1)

so here

a:b=2:3

ie a/b=2/3

so let common multiple be k

ie a=2k b=3k

so here Angle MOX and Angle Angle MOY forms a linear pair

hence then

Angle MOX+Angle MOY=180

b+90+a=180 from (1)

ie a+b=90

2k+3k=90

ie 5k=90

so k=18

so hence Angle MOX=2k=2×18=54 Degrees

Moreover similarly Angle MOX and Angle XON forms a linear pair axiom

hence then

54+c=180

ie c=126 degrees

Answer 2

Answer:

Let ∠ a = 2x, then ∠b = 3x

(sum of angle in linear pair always equal to 180° )

∠XOM + ∠MOP + ∠POY = 180°

∠b + ∠a + ∠POY = 180°

given that ∠POY = 90°

plug this value we get

3x + 2x + 90° = 180°

5x = 90°

x = 18°

a = 2x = 2 × 18 = 36°

b = 3x = 3 ×18 = 54°

MN is a straight line.

sum of angle in linear pair always equal to 180°

so that ∠b + ∠c = 180°

54° + ∠c = 180°

∠c = 180° − 54° = 126°

∠ c = 126°