Last question or q no. 20
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Answer:
i) connect in series
ii)connect in parallel.
Explanation:
i)On connecting in series the R gets divided hence
1/Rf Ω =1/R1 Ω +1/R2 Ω
1/Rf Ω =1/5Ω +1/10Ω
= 1/3Ω
or Rf =3Ω (MIN)
ii) on connecting in Series
Rf Ω = R1 Ω + R2 Ω
Rf Ω = 5Ω +10 Ω
=15Ω (MAX.)
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