Question

last Sunday, priyanka decided to go outside with her family for the dinner in some particular restaurant. Then, she thought to go through her own car. So, while moving she increased the speed of the car from 36km/h to 54km/h. All of sudden , a rickshaw came in front of her car but due to applying of brakes at the right time, both of them got safe from meeting with an accident .

(a) calculate the increase in the speed of the car in the terms of km/h.
(b) Mention a positive action performed by priyanka here.​

Answer 1

Given:

Priyanka while moving in her car, she increased the speed of the car from 36km/h to 54km/h.

To find:

• Increase in speed of car

• Positive action showed by Priyanka

Calculation:

Initial speed = 36 km/hr

Final speed = 54 km/hr

Let increase in speed be ∆v

$\rm{\Delta v = v2 - v1 }$

$= > \rm{\Delta v = 54 - 36}$

$= > \rm{\Delta v = 18 \: km {hr}^{ - 1} }$

So, increase in speed = 18 km/hr.

• Positive action showed by Priyanka : She was driving carefully with the alert mind, such that when she saw the rickshaw coming in front of a car she quickly applied the brakes.

• This prevented any accident and prevented loss of life.