Question

last term of the series x square , x, 1......to 31 term is ​

Answer 1

Answer:

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Answer 2

Answer:

1/x^28✔️

Step-by-step explanation:

Each term is given by Tn=arn−1 where a is the first term and r is the common ratio i.e. Tn+1Tn.

In this case we have r = x/x2 = 1/x and a=x2.

So putting n=31 we have,

T31=x^2(1/x)^31−1

=x^2−30

=x^−28

or 1/x^28 ✔️