Question

last two digits of
(19)¹³¹+ (131)¹^9=?​

Answer 1

90 will be last two digit of 19¹³¹ + 131¹⁹

Step-by-step explanation:

19¹³¹ + 131¹⁹  =

131¹⁹

Formula for Last two digits of numbers ending in 1

Multiply the tens digit of the number (3 here) with the last digit of the exponent (9 here) to get the tens digit. The unit digit will always equal to one.

tens Digit = 3 * 9  = 27 hence 7 will be tens digit

71  will be last two digit of 131¹⁹

19¹³¹ = 19 * 19¹³⁰   = 19 * (19²)⁶⁵ = 19 * (361)⁶⁵

(361)⁶⁵   will end  with  01    ( as  6 * 5 = 30 hence tens digit  = 0  & unit digit would be 1)

now multiplying it with 19

last two digit would be 19

19 will be last two digit of 19¹³¹

71  will be last two digit of 131¹⁹

19 will be last two digit of 19¹³¹

71 + 19

= 90

90 will be last two digit of 19¹³¹ + 131¹⁹

Learn more:

sum of last two digits of 7^2020​ - Brainly.in

https://brainly.in/question/13644367