Last year from school 65 students were seated for an entrance examination. Result was 60% pass. 5 students were detained. What would have been the pass percent?
Answers
Answer:
5/60* is83.33
Step-by-step explanation:
so the answer is 83.33
If 5 students were detained, then the pass percentage would have 87.17%.
Step-by-step explanation:
Total no. of students seated for the examination = 65
Pass % = 60%
∴ No. of students who passed the exam = 60% of 65 = 0.6 * 65 = 39
From the given data of the question that, considering that 5 students were detained from the no. of students who passed in the exam:
So, No. of students passed in the exam excluding the detained students = 39 – 5 = 34
Thus,
The pass percentage would have been given as,
= [{No. of students passed in the exam excluding the detained students} / {No. of students who passed the exam}]* 100
= [34/39] * 100
= 87.17%
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