Question

Lasya is watering the plants in her garden with pipe of cross section A and observed that the force of water from the pipe F. Find the change in area of cross section of the pipe to attain the pressure difference which is 1.5 times that of initial.

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Answer 1

Given:-

cross section area = A

force = F

to find change in area so pressure changer to 1.5 times

as we know,

$p= \frac{f}{a}$

and

$a = \frac{f}{p} - - (1)$

and

as force is constant so,

$a1 = \frac{f}{1.5p}$

$a1 = \frac{1}{1.5} \times \frac{f}{p}$

from equ. 1 we got,

$a1 = \frac{a}{1.5}$

so,

the change in area is 1.5 time less than normal area

Answer 2

Answer:

Given:-

cross section area = A

force = F

to find change in area so pressure changer to 1.5 times

as we know,

p= \frac{f}{a}p=af

and

a = \frac{f}{p} - - (1)a=pf−−(1)

and

as force is constant so,

a1 = \frac{f}{1.5p}a1=1.5pf

a1 = \frac{1}{1.5} \times \frac{f}{p}a1=1.51×pf

from equ. 1 we got,

a1 = \frac{a}{1.5}a1=1.5a

so,

the change in area is 1.5 time less than normal area.

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