Question

lataben borrowed some money from a bank at a rate of 10 p.c.p.a. interest for
$2 \frac{1}{2}$
years to start a cottage industry. if she paid 10250 rupees as total interest , how much money had she borrowed ?​

Answer 1

AnswEr :

$\bold{Given} \begin{cases}\sf{Simple \: Interest=Rs.10250} \\ \sf{Rate=10 \: p.c.p.a.}\\ \sf{Time=2 \frac{1}{2} = \frac{5}{2} \: Yr. }\\ \sf{Principal=?}\end{cases}$

p.c.p.a = Percentage Per Annum

• According to the Question Now :

$\leadsto\sf Simple\: Interest =\dfrac{P \times R \times T}{100}$

$\leadsto\sf 10250 =\dfrac{P \times 10 \times 5}{100 \times 2}$

$\leadsto\sf 10250 =\dfrac{P \times \cancel{50}}{ \cancel{200}}$

$\leadsto\sf 10250 =\dfrac{P}{ 4}$

$\leadsto\sf 10250 \times 4 =P$

$\leadsto \boxed{\sf P =Rs. \: 41000}$

⠀

∴ Lataben had borrowed Rs. 41000.

Answer 2

$\Large\underline{\underline{\sf{Given}:}}$

• Simple interest = Rs.10250
• Time = 2(1/2) = 5/2 years.
• Rate = 10% per annum .

$\large\tt{Question:-}$

• Find the Principal ?

$\LARGE\bold\star\underline{\underline\textbf{Formula\:used}}$ ::::----

$\red{\leadsto \: P = \frac{SI \times 100}{R \times T}}$

Putting values we get,,,,

$\purple{\leadsto \: P = \frac{10250 \times 100}{ \frac{5}{2} \times 10 }} \\ \\ \pink{\leadsto \: P = \frac{10250 \times \cancel{100}}{ \cancel 25 }} \\ \\ \red{\leadsto \: P = \: Rs.41000}$

$\textbf{Hence He Borrowed Rs.41000 From Bank ..}$