Latent heat of ice is 80cal/gm convert it into joule/kg if 1 cal=4.18
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The given value of 1 cal is equal to 4.18
So ,after this you will calculate the answer would by as follow:
80*4.18= 334.4joule/kg
So ,after this you will calculate the answer would by as follow:
80*4.18= 334.4joule/kg
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