Question

Latent heat of steam is 536 cal g . Express it in
J kg
Ans. 2.24 x 100 J kg ?
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Answer 1

so, latent heat for 1g water = 536calorie = 4.18 x 536 = 2240.48 Joule. 2240.48 joule of heat required to convert 1g of water to vapour . so, 2240.48 x 103 joule heat is required to convert 1 kg water into steam .

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