Chemistry, asked by Aryangupta3848, 1 day ago

Latent heat of vaporization of water is----

a). 2.25×10² J/kg
b). 22.5×10⁵ J/kg
c). 3.34×10⁵ J/kg
d). 33.4×10² J/kg​​

Answers

Answered by srijanthapliyal102
5

Answer:

Explanation: The latent heat of vaporization of water is 2.25 × 106 J/kg.

b)The latent heat of vaporization of water is 22.5 × 105 joules per kilogram (or 22.5 × 105 j/kg). Hence it means that 22.5 × 10 5 J of heat is required to change 1 Kg of water (at its boiling point, 100°C) into steam at the same temperature of 100°C.

c) I don't know this one

D)I don't know this

but please mark the answer branist

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