Question

Latent heat of vapourisation of a liquid at 500k
and 1atm pressure is 10K.Cal/mole. What
is the change is internal energy when 3 mole
liquid vapourised at the same temperature ?
(HINT: deltaH = deltaE + deltanRT)​

Answer 1

Answer:

3H2O(l)→3H2O(g)

Δng=3

ΔE=ΔH−ΔngRT

=3×10−3×500×0.002=27Kcal