Question

lateral surface area of a hollow cylinder is 4224 CM square. It is cut along its height and formed a rectangular sheet of width 33 cm find the perimeter of the rectangle?​

Answer 1

QUESTION

Lateral surface area of a hollow cylinder is 4224 CM square. It is cut along its height and formed a rectangular sheet of width 33 cm find the perimeter of the rectangle?

$\Huge\bold{\underline{ANSWER}}$

 

Given:

$\mapsto$ Lateral surface area of hollow cylinder= 4224 cm²

$\mapsto$ Height of a hollow cylinder (h)= 33 cm

SOLUTION:

$\boxed{Lateral\:surface\:area\:or\:curved\:surface\:area\:of\:hollow\:cylinder= 2πrh}$

$\mapsto$ 4224 = 2×(22/7) × r × 33

$\mapsto$ r=(4224×7) / 2×22×33

$\mapsto$ r= (64 × 7)/22

Length of rectangular sheet= 2πr

= 2×(22/7)× (64 × 7)/22

=64 × 2

= 128 cm

Perimeter of rectangular sheet = 2(l+b)

= 2(128+33)

= 2 × 161

= 322 cm

Hence, perimeter of rectangular sheet is 322 cm.