Latesh engagea a Labour to get some repair work.Charges to be paid for this work are zeros of the polynomial x^2-300x+22500. (A) Find the zeros of polynomial.
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HELLO DEAR,
★ ( A ) ★
X² - 300x + 22500 = 0
⇒x² - 150x - 150x - 22500 = 0
⇒x(x - 150) - 150(x - 150) = 0
⇒(x - 150)(x - 150) = 0
⇒x = 150 , x = 150
hence charges to be paid is "150"
I HOPE ITS HELP YOU DEAR,
THANKS
★ ( A ) ★
X² - 300x + 22500 = 0
⇒x² - 150x - 150x - 22500 = 0
⇒x(x - 150) - 150(x - 150) = 0
⇒(x - 150)(x - 150) = 0
⇒x = 150 , x = 150
hence charges to be paid is "150"
I HOPE ITS HELP YOU DEAR,
THANKS
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