Question

Lattice constant of cu is 0.38nm then the distance between the plane (110) is
OptionA) 0.376nm
OptionB)0.27nm
optionC)0.17nm
OptionD)0.576nm

Answer 1

Answer:

(b) the interplanar spacing of {110} planes. ... ( a) The answer can be found by looking at a unit cell of Cu (FCC). ... Determine the lattice parameter and look at the unit cell occupation.

Hope it helps to u.....

Answer 2

Answer: Option B) 0.27nm

Concept: The distance between planes in FCC structure is given by

                dhkl = a/[(h^2)+(k^2)+(l^2)]^0.5

                 where a = lattice constant

                 hkl = plane(hkl)

Given: Lattice constant of cu is 0.38nm

           Plane(110)   ( h=1 k=1 l=0 )

To find: The distance between the plane (110)

Step by step explanation:

Lattice constant of cu is 0.38nm

Cu has Face centered cubic (FCC) structure

For FCC structure distance between planes is given by

 dhkl = a/[(h^2)+(k^2)+(l^2)]^0.5

The distance between the plane (110) is given by

d(110) = a/[(h^2)+(k^2)+(l^2)]^0.5

d(110) = 0.38/[(1^2)+(1^2)+(0^2)]^0.5

d(110) = 0.38/[(1)+(1)+(0)]^0.5

d(110) = 0.38/[2]^0.5

d(110) = 0.27nm

Answer: The distance between the plane (110) is 0.27nm

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