Chemistry, asked by madhulika0, 1 year ago

lattice energy of potassium fluoride is higher than potassium iodide explain​

Answers

Answered by Solankiyash927
1

Answer:

The two main factors affecting lattice energy are the charges on the ions and the distance between the ions.

In magnesium chloride, 2+ ions are attracting 1- ions. In potassium iodide, the attraction is between 1+ and 1- ions.

Thus, the lattice energy of  

KI

should be less than that of  

MgCl

2

.

In  

NaBr

, the attraction is between 1+ and 1- ions.

In  

KI

,

K

+

is a bigger ion than  

Na

+

and  

I

-

is a bigger ion than  

Br

-

.

The distance between ions is greater in  

KI

, so  

KI

should have a lower lattice energy and a lower melting point than  

NaBr

.

A simple extrapolation from  

NaCl

through  

NaBr

suggests that  

KI

should have a lattice energy of about 680 kJ/mol and a melting point of about 700 °C.

The actual values are 698 kJ/mol and 681 °C.

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