LAUPICS
Example 2. A tennis ball is thrown up a
reaches a height of 4.05 m before coming
down. What was its initial velocity? How
much total time will it take to come down
Assume g = 10 m/s2
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Answer:
ball is thrown up
hence v=O m/s
s=40.5 m
g= (-10)
v^2 = u^2 + 2gs
O. = u^2 + 2*(-10)*40.5
0. =. u^2 + (-81)
u^2 =. 81
u = 9 m/s
initial velocity 9m/s
s = ut + 1/2 gt^2
40.2 = o + 1/2 (-10)* t^2
40.2.=. (-5)* t^2
t^2. = 40.5/5
t^2. =. 8.1
t. = 9 s
total time = 9s + 9s
= 18 s
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