Question

Lavanti throws a pair of dice and records the product of the numbers appearing on the
dice. Pihu throws 1 dice and records the squares the number that appears on it. Who
has the better chance of getting the number 36? Justify?​

Answer 1

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total no. of outcomes n(s) = 36

number of outcomes for getting product 36,

           n(E1)= 1(6*6)

therefore probability for jayanti =  n(E1)/nS = 1/36

E1pihu throw one dice

so total no. of outcomes n(s) = 6

number of outcomes for getting square of a number is 36

                            n(E2) = 1

therefore probability for pihu =n(E2)/nS = 1/6

   hence, pihu has better chance of getting the number 36

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#Maks#

Answer 2

Hyy mate

I ask you something

Do you know Arshbilga

Please answer me fast

And stay away from Arshbilga