Question

Law of constant properties stipulate that in water the mass of hydrogen to that of oxygen is always 1:8.If 27 grams of water os decomposed what would be the mass of the oxygen obtained from it.
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Answer 1

Answer:

24 gm

Explanation:

Since the ratio is a constant 1:8 for H:O, in 9 grams of water, 1 gram will be hydrogen and 8 grams will be oxygen to maintain the ratio. Thus, in 9*3 = 27 grams of water, we will have 1*3 = 3 grams of hydrogen, and 8*3 = 24 grams of oxygen.

Alternatively, let there be x grams of hydrogen in the given water sample. Thus, there will be 8x grams of oxygen to maintain the ratio.

Total weight = x + 8x = 9x grams.

Given, total weight of water = 27 grams.

Thus, 9x = 27 grams

x = 3 grams.

Thus, weight of oxygen on decomposing 27 grams of water will be 8x = 8*3 = 24 grams.