Question

Laws of exponents forumals

Answer 1

hope this will  help u

Answer 2

Answer:

$x^{1} = x$

$x^{0} = 1$

$x^{-1} = 1/x$

$x^{m} x^{n} = x^{m+n}$

$x^{m} /x^{n} = x^{m-n}$

$(x^{m} ){n} = x^{mn}$

$(xy)^{n} = x^{n} y^{n}$$(x/y)^{n} = x^{n} /y^{n}$

$x^{-n} = 1/x^{n}$

$x^{m/n} = \sqrt[n]{x^{m}} = (\sqrt[n]{x})^{2}$

Step-by-step explanation: