laws of motion sums
Answers
Answer:
If an object has gently dropped towards the ground and it takes 10 s to reach the ground. Find the distance between the initial point of the object from the ground..(take g as 10m/s^2)
Explanation:
Ans-. initial velocity (u) = 0m/s
time taken(t) = 10s
acceleration due to gravity(a)= 10m/s^2
final velocity(v) = u + at
therefore.... v = 0 + 10 × 10
that is equal to= 100 m/s
now
v^2 -u^2= 2as
(100)^2 -0^2= 2 ×10 × (s)
10000=20(s)
therefore... Distance = 10000÷20 = 500m
HOPE IT HELPS ^_^
Answer:
1) 1st equation formula -v=u+at
(2) 2nd equation formula -s=ut+1/2at^2
(3)3rd equation formula -v^2=v^2+at
(4)momentum=mass × velocity
(5)force=mass ×acceleration
(6) acceleration =change in velocity /time take
(7)speed =distance /time
(8)velocity =displacement /time