Question

laws of motion sums​

Answer 1

Answer:

If an object has gently dropped towards the ground and it takes 10 s to reach the ground. Find the distance between the initial point of the object from the ground..(take g as 10m/s^2)

Explanation:

Ans-. initial velocity (u) = 0m/s

time taken(t) = 10s

acceleration due to gravity(a)= 10m/s^2

final velocity(v) = u + at

therefore.... v = 0 + 10 × 10

that is equal to= 100 m/s

now

v^2 -u^2= 2as

(100)^2 -0^2= 2 ×10 × (s)

10000=20(s)

therefore... Distance = 10000÷20 = 500m

HOPE IT HELPS ^_^

Answer 2

Answer:

1) 1st equation formula -v=u+at

(2) 2nd equation formula -s=ut+1/2at^2

(3)3rd equation formula -v^2=v^2+at

(4)momentum=mass × velocity

(5)force=mass ×acceleration

(6) acceleration =change in velocity /time take

(7)speed =distance /time

(8)velocity =displacement /time