Math, asked by 9229984, 5 months ago

Layana’s house is located at (2 and two-thirds, 7 and one-third) on a map. The store where she works is located at (–1 and one-third, 7 and one-third). What is the distance from Layana’s home to the store?

Answers

Answered by pulakmath007
5

SOLUTION

GIVEN

Layana’s house is located at

  \displaystyle \sf{ \bigg( \: 2 \frac{2}{3} \:  , \: 7 \frac{1}{3}  \bigg)}

on a map. The store where she works is located at

  \displaystyle \sf{ \bigg( \: -  1 \frac{1}{3} \:  , \: 7 \frac{1}{3}  \bigg)}

TO DETERMINE

The distance from Layana’s home to the store

EVALUATION

Here it is given that

Layana’s house is located at

  \displaystyle \sf{ \bigg( \: 2 \frac{2}{3} \:  , \: 7 \frac{1}{3}  \bigg)}

The store where she works is located at

  \displaystyle \sf{ \bigg( \: -  1 \frac{1}{3} \:  , \: 7 \frac{1}{3}  \bigg)}

  \displaystyle \sf{ So \: the \:  ordinate \:  of \:  both  \: the  \: points \:  is \: =  7 \frac{1}{3} }

So the required distance

  \displaystyle \sf{ = \sqrt{{\bigg( \: 2 \frac{2}{3} \:  +  \: 1 \frac{1}{3}  \bigg) }^{2} +{\bigg( \: 7 \frac{1}{3} \:    - \: 7 \frac{1}{3}  \bigg) }^{2} }    }

  \displaystyle \sf{ = \sqrt{{\bigg( \:  \frac{8}{3} \:  +  \:\frac{4}{3}  \bigg) }^{2} +{(0)}^{2} }    }

  \displaystyle \sf{ = \sqrt{{\bigg( \:  \frac{12}{3} \:    \bigg) }^{2}  }    }

  \displaystyle \sf{ = \sqrt{{   {(4)}^{2} }}    }

  \displaystyle \sf{ = 4 \:  \: unit  }

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