Question

LCM= 728 , HCF=4,SECOND NUMBER =52 Find the remaining values based on the given values.

Please answer as soon as possible
Will mark you as the brainliest!!!!!!​

Answer 1

Answer:

✅Here's your answer....

#LCM×HCF = Product of two numbers

#Given..

HCF= 4, LCM=728 Second number = 52

#First number be x

#LCM×HCF = Product of two numbers

#728 ×4 = x×52

$\frac{728 \times 4}{52} = x \\ \\ \\ 56 = x$

#Therefore the required number is 56...

Hope it helps ✌

Answer 2

Answer:

lcm=728

hcf=4, number=52

second no=x

lcm*hcf=product of no

728*4=52*x

x=728*4/52

x=56