Question

lcm and hcf of 2 numbers are 341 and 11 respectively. find greater of two numbers

Answer 1

Hi there!
Here's the answer :

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Let the two No.s be x & y

HCF(x,y) = 11

=> x = 11m & y=11n ; where m & n are being relatively prime

LCM(x,y) = 341
=> 11mn = 341
=> mn = 341/11
=> mn = 31

Here, 31 is a prime
but m & n are relatively prime

There should not exist any such integer but m = 1 & n = 31 is a trivial solution

Hence
x = 11 & y = 341 is the only solution

•°• 341 is the greater No. of the two.

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Hope it helps

Answer 2

Answer:

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Step-by-step explanation:

341÷11=31

31 is a prime no.

so the greatest no. is 341

hence the answer is 341