Question

LCM and HCF of two numbers are 144 and 12 respectively then find their product​

Answer 1

Answer:

Let the numbers be 12x;12y, where x,y are co-prime to each other.

We know that Product of two numbers =LCM×HCF

Then 12x×12y=144×12

=>xy=12

Now, we need to find co-prime numbers whose product is 12

12=22×3

Therefore co-prime pairs will be (1,12);(4,3)

Therefore, only two pairs of such numbers satisfy the given condition

Step-by-step explanation:

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Answer 2

Correct option is

A

2

Let the numbers be 12x;12y, where x,y are co-prime to each other.

We know that Product of two numbers =LCM×HCF

Then 12x×12y=144×12

=>xy=12

Now, we need to find co-prime numbers whose product is 12

12=2

2

×3

Therefore co-prime pairs will be (1,12);(4,3)

Therefore, only two pairs of such numbers satisfy the given condition.

Step-by-step explanation:

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