LCM and HCF of two numbers are 144 and 12 respectively then find their product.
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Let the numbers be 12x;12y, where x,y are co-prime to each other.
We know that Product of two numbers =LCM×HCF
Then 12x×12y=144×12
=>xy=12
Now, we need to find co-prime numbers whose product is 12
12=2
2 ×3
Therefore co-prime pairs will be (1,12);(4,3)
Therefore, only two pairs of such numbers satisfy the given condition.
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Let the numbers be 12x;12y, where x,y are co-prime to each other.
We know that Product of two numbers =LCM×HCF
Then 12x×12y=144×12
=>xy=12
Now, we need to find co-prime numbers whose product is 12
12=2
2
×3
Therefore co-prime pairs will be (1,12);(4,3)
Therefore, only two pairs of such numbers satisfy the given condition.
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