Question

LCM and hcfproblems addition subtraction multiplication problems​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Here we will get the idea how to solve the word problems on H.C.F and L.C.M.

1. Find the smallest number which on adding 19 to it is exactly divisible by 28, 36 and 45.

First we find the least common multiple (L.C.M.) of 28, 36 and 45.

Word problems on H.C.F. and L.C.M.

9Save

Therefore, least common multiple (L.C.M.) of 28, 36 and 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260

Therefore, the required number = 1260 - 19 = 1241