LCM and hdf of 3/4 and 2/5
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Note 2 and 3 are primes and 4=22=2×2
lcm(a,b)=a×bhcf(a,b)
lcm(a,b,c)=lcm(lcm(a,b),c)
hcf(a,b,c)=hcf(hcf(a,b),c)
hcf≡gcd
lcm(2,4)=4
hcf(2,4)=2
lcm(2,3)=6
hcf(2,3)=1
lcm(3,4)=12
hcf(3,4)=1
hcf(2,3,4)=hcf(hcf(2,4),3)=1
lcm(2,3,4)=lcm(lcm(2,4),3)=12
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