Math, asked by ranjanamokati, 9 months ago

lcm n hcf of 12,72,1087also verify that Lcm*hcf=product of numbers​

Answers

Answered by samyak5926
1

Answer:

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Answered by srinuchokkaku66
0

Answer:

The prime factors of the numbers 12, 72 and 120,

12=2\times 2\times 312=2×2×3

72=2\times 2\times 2\times 3\times 372=2×2×2×3×3

120=2\times 2\times 2\times 3\times 5120=2×2×2×3×5

HCF is the highest common factor,

HCF(12,72,120)=2\times 2\times 3HCF(12,72,120)=2×2×3

HCF(12,72,120)=12HCF(12,72,120)=12

LCM is the least common factor,

LCM(12,72,120)=2\times 2\times 2\times 3\times 3\times 5LCM(12,72,120)=2×2×2×3×3×5

LCM(12,72,120)=360LCM(12,72,120)=360

Now, Product of three numbers

P=12\times 72\times 120P=12×72×120

P=103680P=103680

Multiple of HCF and LCM,

HCF\times LCM=12\times 360HCF×LCM=12×360

HCF\times LCM=4320HCF×LCM=4320

As HCF and LCM is not equal to the product of three given numbers.

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