Question

LCM of 164 in square root​

Answer 1

answer:

Here we have to find the prime factors of 162.

Divide 162 by 2;

162 ÷ 2 = 81

Divide 81 by 3

81 ÷ 3 = 27

Divide 27 by 3

27 ÷ 3 = 9

Divide 9 by 3

9 ÷ 3 = 3

Then divide 3 by 3

3 ÷ 3 = 1

So the prime factorisation of 162 is

162 = 2 X 3 X 3 X 3 X 3

Now we know the values of √3, √5 and √7 we get

On paring the factors we get

162 = 2 X (3 X 3) X(3 X 3)

√162= √2 X (3 X 3) X(3 X 3)

√162= 3 x 3 x √2

√162= 9√2

Answer

Hence The square root of 162 is 9√2

Hence, √162 = 9√2