LCM of 2520 6600 is 252 into ke then find the value of k
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Hey dear !!
Here is yr answer
_____________________________
Given,
LCM of 2520 and 6600 is 252 × k
value of k = ??
Now,
Find the HCF of 2520 and 6600
According to euclid's division algorithm---
6600>2520
6600 = 2520 × 2 + 1560
2520 = 1560 × 1 + 960
1560 = 960 × 1 + 600
960 = 600 × 1 + 360
600 = 360 × 1 + 240
360 = 240 × 1 + 120
240 = 120 × 2 + 0
HCF = 120
And,
HCF × LCM = product of two nos.
120 × 252k = 2520 × 6600
252k = 2520 × 6600 / 120
252k = 2520 × 55
k = 2520 × 55 / 252
k = 10 × 55
k = 550
Therfore , value of k = 550
Hope it hlpz....
Here is yr answer
_____________________________
Given,
LCM of 2520 and 6600 is 252 × k
value of k = ??
Now,
Find the HCF of 2520 and 6600
According to euclid's division algorithm---
6600>2520
6600 = 2520 × 2 + 1560
2520 = 1560 × 1 + 960
1560 = 960 × 1 + 600
960 = 600 × 1 + 360
600 = 360 × 1 + 240
360 = 240 × 1 + 120
240 = 120 × 2 + 0
HCF = 120
And,
HCF × LCM = product of two nos.
120 × 252k = 2520 × 6600
252k = 2520 × 6600 / 120
252k = 2520 × 55
k = 2520 × 55 / 252
k = 10 × 55
k = 550
Therfore , value of k = 550
Hope it hlpz....
simma2:
thanks
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